document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1101528>Question 1101528</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a sum of money amounting to 5.55 consistsof 25cents and 1 peso coins.If there are 27 coins in all, how many each kind are there.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805332 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805332\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p = number of 1-peso coins<BR>\n" );
document.write( "q = number of 25-peso coins\r<BR>\n" );
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document.write( "p + q = 27<BR>\n" );
document.write( "p + 25q = 555\r<BR>\n" );
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document.write( "Multiply the first equation by 25. We are planning to eliminate the variable q.\r<BR>\n" );
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document.write( "25p + 25q = 675<BR>\n" );
document.write( "p + 25q = 555\r<BR>\n" );
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document.write( "Subtract to get 24p = 120, so p = 5.\r<BR>\n" );
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document.write( "There are 5 pennies and 22 quarters. </SPAN>\n" );
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