document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1023011>Question 1023011</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Megan has $1.10 in dimes,nickels, and pennies.She has three times as many nickels as pennies, and the number of dimes is two less than the number of pennies. How many dimes, nickels, and pennies does she have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805329 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805329\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p = number of pennies<BR>\n" );
document.write( "n = number of nickels<BR>\n" );
document.write( "d = number of dimes\r<BR>\n" );
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document.write( "n = 3p<BR>\n" );
document.write( "d = p - 2<BR>\n" );
document.write( "p + 5n + 10d = 110\r<BR>\n" );
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document.write( "Write everything in terms of p.\r<BR>\n" );
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document.write( "p + 5n + 10d = 110<BR>\n" );
document.write( "p + 5(3p) + 10(p-2) = 110<BR>\n" );
document.write( "p + 15p + 10p - 20 = 110<BR>\n" );
document.write( "26p = 130<BR>\n" );
document.write( "p = 5\r<BR>\n" );
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document.write( "Megan has 5 pennies, 15 nickels, and 3 dimes. </SPAN>\n" );
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