document.write( "Question 989185: One half the sum of three consecutive numbers added to twice the first number is equal to 63, find the smallest integer \n" ); document.write( "
Algebra.Com's Answer #805291 by CubeyThePenguin(3113)![]() ![]() You can put this solution on YOUR website! three consecutive numbers: (x-1), x, (x+1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "((x-1) + x + (x+1))/2 + 2x = 63 \n" ); document.write( "3x/2 + 2x = 63 \n" ); document.write( "7x/2 = 63 \n" ); document.write( "x = 18\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The smallest integer is x-1 = 17. \n" ); document.write( " |