document.write( "Question 993252: The sum of three integers is 299. The sum of the first and second integers exceeds the third by 71. The third integer is 11 less than the first. Find the three integers. \n" ); document.write( "
Algebra.Com's Answer #805280 by CubeyThePenguin(3113) You can put this solution on YOUR website! x + y + z = 299 \n" ); document.write( "x + y = z + 71 \n" ); document.write( "z = x - 11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute z = x - 11 into the other equations:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x + y = 310 \n" ); document.write( "x + y = x - 11 + 71\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 60\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x + (60) = 310 \n" ); document.write( "2x = 250 \n" ); document.write( "x = 125\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z = 125 - 11 = 114\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The integers are x = 125, y = 60, and z = 114. \n" ); document.write( " |