document.write( "Question 1177052: A fair die is tossed twice.find the probability of getting 4,5, or 6 on the first toss and a 1,2,3 or 4 on the second toss. \n" ); document.write( "
Algebra.Com's Answer #805272 by ikleyn(52864)\"\" \"About 
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document.write( "The probability of getting 4, 5, or 6 on the first toss  is  \"3%2F6\" = \"1%2F2\".\r\n" );
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document.write( "The probability of getting 1, 2, 3, or 4 on the second toss is  \"4%2F6\" = \"2%2F3\".\r\n" );
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document.write( "The outcomes of the first and the second toss are INDEPENDENT, so the final answer is the product\r\n" );
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document.write( "    P = \"%281%2F2%29%2A%282%2F3%29\" = \"1%2F3\".    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "To solve the problem, there is NO any need to present the table of the 36 outcomes, as @ewatrrr does.\r
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\n" ); document.write( "\n" ); document.write( "There is no any need to spend your time to construct and to write this table,\r
\n" ); document.write( "\n" ); document.write( "as well as there is no any need to spend your time counting the number of favorable outcomes from this table.\r
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