document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1177068>Question 1177068</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The drug Ziac is used to treat hypertension. In a clinical test it was found 3.2% of 225 Ziac users experienced dizziness. Construct a 95% confidence interval to estimate the proportion ofall Ziac users who experience dizziness </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805269 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805269\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This has a half-interval of z(0.975)*sqrt(p*(1-p)/n)<BR>\n" );
document.write( "or 1.96* sqrt (0.032*0.968/225)<BR>\n" );
document.write( "=0.0230<BR>\n" );
document.write( "so 95%CI=(0.009, 0.055) proportion of people with dizziness<BR>\n" );
document.write( "The calculator will give (0.008, 0.54) because 3.2% of 225 is 7.2, and we have to use integers here or 7, which will give a slightly different interval. </SPAN>\n" );
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