document.write( "Question 1177057: Show that (x-1) (x+1) is a factor of f(x)=3x^50-3 \n" ); document.write( "
Algebra.Com's Answer #805262 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=3x%5E50-3\"\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=3%28x%5E50-1%29\"\r
\n" ); document.write( "\n" ); document.write( "zeros are\r
\n" ); document.write( "\n" ); document.write( "\"3%28x%5E50-1%29=0\"....since factor \"3%3C%3E0\", we have\r
\n" ); document.write( "\n" ); document.write( "\"x%5E50-1=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E50=1\"\r
\n" ); document.write( "\n" ); document.write( "\"x=root%2850%2C1%29\".....no matter what root is it, solutions are\r
\n" ); document.write( "\n" ); document.write( "\"x=1\" or \"x=-1\"\r
\n" ); document.write( "\n" ); document.write( "using root product theorem, we have \r
\n" ); document.write( "\n" ); document.write( " \"%28x-1%29+%28x%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "so, it is a factor of \"f%28x%29=3x%5E50-3\"\r
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