document.write( "Question 1177055: 1. A and B play 12 games of chess of which 6 are won by A,4 are won by B and two ends in a tie. They agree to play a tournament consisting of 3 games. Find the probability that\r
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document.write( "a) A wins all three games
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document.write( "b) Two games end in a tie
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document.write( "c) A and B wins alternatively
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document.write( "d) B wins at least one game \n" );
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Algebra.Com's Answer #805254 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Hi\r\n" ); document.write( "12games: A wins 6, B wins 4, 2 T\r\n" ); document.write( "Play 3 games:\r\n" ); document.write( "a) P(A wins all three games) = (1/2)(1/2)(1/2) = 1/8\r\n" ); document.write( "b) P(Two games end in a tie) = (3C2)(5/6)(1/6)(1/6) = 15/216\r\n" ); document.write( "c) P(A and B wins alternatively) = \r\n" ); document.write( "P(ABA) + P(BAB) = (1/2)(1/3)(1/2) + (1/3)(1/2)(1/3) = 1/12 + 1/18 = 30/12*18 = 5/36\r\n" ); document.write( "\r\n" ); document.write( "d) P( B wins at least one game) = 1 - P(wins NO games) = 1- 1/8 = 7/8\r\n" ); document.write( "\r\n" ); document.write( "Wish You the Best in your Studies.\r\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |