document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1177020>Question 1177020</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Topic: Similarities (I don't know if proofs is the right section)<BR>\n" );
document.write( "Chord AB on circle C of radius 3 intersects at diameter X. If AX = 3...\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805228 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805228\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Label the endpoints of the diameter D and E, with D the endpoint closer to B.<br><BR>\n" );
document.write( "Let x be the length of CX that we are to find.<br><BR>\n" );
document.write( "Then CD is 3-x and CE is 3+x.<br><BR>\n" );
document.write( "When two chords intersect inside a circle, the product of the lengths of the two parts of one chord is equal to the product of the lengths of the two parts of the other chord.<br><BR>\n" );
document.write( "In this problem, that gives us<br><BR>\n" );
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document.write( "That equation is easily solved to find the answer to the problem.<br><BR>\n" );
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