document.write( "Question 1177017: Find the standard form of the equation of the hyperbola with the given characteristics.\r
\n" ); document.write( "\n" ); document.write( "Vertices: (−5, 5), (5, 5); foci: (−6, 5), (6, 5)
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Algebra.Com's Answer #805221 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
Standard form: \r
\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "foci: (\"-6\",\"5\"), (\"6\",\"5\") \r
\n" ); document.write( "\n" ); document.write( "since foci is at (\"c\",\"5\") =>\"c=6\"\r
\n" ); document.write( "\n" ); document.write( "vertices:(\"-5\",\"5\"), (\"5\",\"5\")\r
\n" ); document.write( "\n" ); document.write( "since vertices is at (\"a\",\"5\") =>\"a=5\"\r
\n" ); document.write( "\n" ); document.write( "then \r
\n" ); document.write( "\n" ); document.write( "\"b%5E2=c%5E2-a%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2=6%5E2-5%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2=36-25\"\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2=11\"\r
\n" ); document.write( "\n" ); document.write( "so, your equation is:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F25-%28y-5%29%5E2%2F11=1\"\r
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