document.write( "Question 1176504: In triangle ABC, the angle bisector AL meets the median BM at E.
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document.write( "EM = 200 and BE = 300, and AL divides BC into two segments of length BL = 600 and LC = x.
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document.write( "Find the value of x.\r
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document.write( "All I was able to do so far is draw a picture but I'm stuck. Please help? Thanks! \n" );
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Algebra.Com's Answer #805209 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The tutor @manath has the correct drawing and correct final answer of x = 800\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "However, this is from solving the equation 300/400 = 600/x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you solved 300/400 = 600/(600+x), then you would get x = 200 instead which is not correct. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The equation 300/400 = 600/x is due to AB/AC = BL/LC (angle bisector theorem). \n" ); document.write( " \n" ); document.write( " |