document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1176988>Question 1176988</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The height of a triangle is 8m more than twice the length of the base. The area of the triangle is 21 m^2. Find the height of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805138 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805138\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of triangle = 1/2 * base * height\r<BR>\n" );
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document.write( "Let length of base be x\r<BR>\n" );
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document.write( "21 = 1/2 * x * (2x+8)\r<BR>\n" );
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document.write( "42 = x(2x+8)<BR>\n" );
document.write( "42 = 2x^2 +8x\r<BR>\n" );
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document.write( "2x^2 +8x -42 =0<BR>\n" );
document.write( "divide equation by 2<BR>\n" );
document.write( "x^2+4x-21=0<BR>\n" );
document.write( "(x+7)(x-3)=0<BR>\n" );
document.write( "x =-7 or x=3\r<BR>\n" );
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document.write( "taking positive value\r<BR>\n" );
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document.write( "x=3\r<BR>\n" );
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document.write( "base =3 <BR>\n" );
document.write( "height = 2x+8 = 14 m\r<BR>\n" );
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document.write( " </SPAN>\n" );
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