document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1176986>Question 1176986</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Forty ounces of a 40% gold alloy are mixed with 60 oz of a 10% gold alloy. Find the percent concentration of the resulting gold alloy. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805134 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805134\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Forty ounces of a 40% gold alloy are mixed with 60 oz of a 10% gold alloy.<BR>\n" );
document.write( " Find the percent concentration of the resulting gold alloy.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "let x = resulting percent in decimal form<BR>\n" );
document.write( "mixture total: 40 + 60 = 100 oz<BR>\n" );
document.write( ":<BR>\n" );
document.write( "100x = .4(40) + .1(60)<BR>\n" );
document.write( "100x = 16 + 6<BR>\n" );
document.write( "100x = 22<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=22%2F100 ALIGN=MIDDLE  ALT=\"22%2F100\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = .22 which is 22% gold concentration </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );