document.write( "Question 1007932: If the 4th term of a geometric sequence is 15 and the 7th term is 405, find the common ratio, and the first term \n" ); document.write( "
Algebra.Com's Answer #805106 by CubeyThePenguin(3113)\"\" \"About 
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a = first term, r = third term\r
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\n" ); document.write( "\n" ); document.write( "ar^3 = 15
\n" ); document.write( "ar^7 = 405\r
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\n" ); document.write( "\n" ); document.write( "Divide equation 2 by equation 1:\r
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\n" ); document.write( "\n" ); document.write( "(ar^7)/(ar^3) = 405/5 = 81 = r^4\r
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\n" ); document.write( "\n" ); document.write( "r = 3 or -3, so a = 15/27 = 5/9.\r
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