document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1027745>Question 1027745</A>: <I><SPAN STYLE=\"word-break: break-all;\"> jonny holds his pen on a paper that creates a linear pair. one of the angles measures 13x+7. the measure of the second angle is one less that twice the first angle. find x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805105 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805105\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> measure of first angle = y\r<BR>\n" );
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document.write( "y + (2y-1) = 180<BR>\n" );
document.write( "3y - 1 = 180<BR>\n" );
document.write( "3(13x + 7) = 181<BR>\n" );
document.write( "39x + 21 = 181<BR>\n" );
document.write( "39x = 170<BR>\n" );
document.write( "x = 170/39 </SPAN>\n" );
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