document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1156666>Question 1156666</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4.<BR>\n" );
document.write( "https://answers.yahoo.com/question/index?qid=20200421142705AAtmH9X </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805073 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805073\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> question: Find the Lateral Area, Surface Area , and Volume of each prism. Leave answers in terms of pi or radicals or fractions .?\r<BR>\n" );
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document.write( "[diagram is a triangular prism with equilateral triangle bases (6 in side length) and height 17 in]\r<BR>\n" );
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document.write( "volume: base * height<BR>\n" );
document.write( "= (6^2 * sqrt(3))/4 * 17<BR>\n" );
document.write( "= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=153sqrt%283%29 ALIGN=MIDDLE  ALT=\"153sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > in^3\r<BR>\n" );
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document.write( "surface area = 2(triangle base area) + 3(rectangle)<BR>\n" );
document.write( "= 2(6^2 * sqrt(3))/4 + 3(6 * 17)<BR>\n" );
document.write( "= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=18sqrt%283%29+%2B+306 ALIGN=MIDDLE  ALT=\"18sqrt%283%29+%2B+306\"   DISABLED_style= \"max-width:90%; height:auto;\" > in^2\r<BR>\n" );
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document.write( "lateral surface area = 3(rectangle) ---> don't include the bases<BR>\n" );
document.write( "= 3(6 * 17)<BR>\n" );
document.write( "= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=306 ALIGN=MIDDLE  ALT=\"306\"   DISABLED_style= \"max-width:90%; height:auto;\" > in^2 </SPAN>\n" );
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