document.write( "Question 110417: Find the derivative of the function with respect to x:\r
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Algebra.Com's Answer #80505 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%28d%2Fdx%29%28sqrt%282-3x%5E2%29%29\" Start with the given function\r
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\n" ); document.write( "\n" ); document.write( "\"%28d%2Fdx%29%281%2F2sqrt%282-3x%5E2%29%29\" Take the derivative of \"sqrt%28A%29\" (just the outside function) to get \"1%2F2sqrt%28A%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28d%2Fdx%29%281%2F2sqrt%282-3x%5E2%29%29%2A%28-6x%29\" Now take the derivative of the inside function \"2-3x%5E2\" to get \"-6x\". Multiply \"-6x\" by \"1%2F2sqrt%282-3x%5E2%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28-3x%29%2F%28sqrt%282-3x%5E2%29%29\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the derivative of \"sqrt%282-3x%5E2%29\" with respect to x is \r
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\n" ); document.write( "\n" ); document.write( "\"%28-3x%29%2F%28sqrt%282-3x%5E2%29%29\"
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