document.write( "Question 1176901: Water shoots out from a fountain at 40 m/s at an angle of 55° above the horizontal.\r
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Algebra.Com's Answer #805036 by ikleyn(52803)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "            The solution / (the calculations)  in the post by   @mananth are     INCORRECT.\r
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document.write( "Vertical component of the initial velocity is  \"V%5Bvert%5D\" = 40*sin(55°) = 40*0.8189 = 32.75 m/s.\r\n" );
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document.write( "The time for water to get the maximum height is  \"T%5Bmax_height%5D\" = \"V%5Bvert%5D%2Fg\" = \"32.75%2F10\" = 3.28 seconds.\r\n" );
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document.write( "The time of the flight is  (assuming that the hose is at the ground level)\r\n" );
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document.write( "    \"T%5Bflight%5D\" = \"2%2AT%5Bmax_height%5D\" = 2*3.28 = 6.55 seconds.\r\n" );
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document.write( "The maximum height = \"%28g%2AT%5Bmax_height%5D%5E2%29%2F2\" = \"%2810%2A3.28%5E2%29%2F2\" = 53.8 meters.\r\n" );
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\n" ); document.write( "\n" ); document.write( "What is  \"the range\"  in your last question is unclear to me,  so I stop my solution at this point.\r
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