document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=258927>Question 258927</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -282-(+1,017)=<BR>\n" );
document.write( "given the formulak=lmn what is the formula for finding the answer to m<BR>\n" );
document.write( "simplify and solve this equation 4m+9+5m-12=42<BR>\n" );
document.write( "solve this equation -9h-6+12h+40=22 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #804872 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=804872\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -282 - 1017 = -1299\r<BR>\n" );
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document.write( "k = lmn ---> m = k/ln\r<BR>\n" );
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document.write( "4m + 9 + 5m - 12 = 42<BR>\n" );
document.write( "9m = 45<BR>\n" );
document.write( "m = 5\r<BR>\n" );
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document.write( "-9h - 6 + 12h + 40 = 22<BR>\n" );
document.write( "3h = -12<BR>\n" );
document.write( "h = -4 </SPAN>\n" );
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