document.write( "Question 1176893: In a given triangle, one side is thrice as long as the shortest side, while the third is 4 inches more than twice the shortest side. Find the perimeter of the triangle in terms of the shortest side x. If the perimeter is 54 inches, how long is each of the sides? \n" ); document.write( "

Algebra.Com's Answer #804867 by ikleyn(52790) $\"\"$ $\"About$

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document.write( "    x + 3x + (2x+4) = 54\r\n" );
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document.write( "        6x =        = 54 - 4 = 50\r\n" );
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document.write( "         x                   =  = 8   inches.\r\n" );
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document.write( "The sides are  x = 8   inches (shortest);  3x = 25 inches (\"one side\")  and  (2x+4) = 20   inches  (\"the third side\").\r\n" );
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document.write( "As always, when you solve such problems, you must check at the end if the triangle inequalities \r\n" );
document.write( "are held (to check if a triangle with such sides does really exist).\r\n" );
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document.write( "In this case, the triangle inequalities are valid, so such a triangle does exist.\r\n" );
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