document.write( "Question 110446: I am trying to graph a quadratic equation....everything was going fine until I tried to get the points for the left side of the graph....they're all over the place...some go below the vertex and it definatly doesnt look like a parabola. Can someone please explain to me how to get the -points? I tried plugging x into the equation but its not working at all...neither are the x and y intercepts, which I have as y=-4 and x=4 and -1, I'm getting so frustrated. The equation is X²+3x-4
\n" ); document.write( " I appreciate anyones help!
\n" ); document.write( " Bonnie C.
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Algebra.Com's Answer #80484 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
y=x^2+3x-4
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y=+x%5E2+%2B3x+-4%29+\" (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = x^2 +3x -4).
\n" ); document.write( "some of the points are (0,-4) obtained by setting x=0 & solving for y
\n" ); document.write( "setting y=0 & solving for x we get
\n" ); document.write( "x^2+3x-4=0
\n" ); document.write( "(x+4)(x-1)=0
\n" ); document.write( "x+4
\n" ); document.write( "x=-4 answer. (-4,0)
\n" ); document.write( "x-1=0
\n" ); document.write( "x=1 answer. (1,0)
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