document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=306752>Question 306752</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having difficulty with this problem and the order of the operations: (16)/(-2)^3 - 5[3-1+2(4-7)] </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #804824 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=804824\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 16/((-2)^3) - 5[3 - 1 + 2(4 - 7)]<BR>\n" );
document.write( "= 16/(-8) - 5(2 + 2(-3))<BR>\n" );
document.write( "= -2 - 5(2 - 6)<BR>\n" );
document.write( "= -2 - 5(-4)<BR>\n" );
document.write( "= -2 + 20<BR>\n" );
document.write( "= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=18 ALIGN=MIDDLE  ALT=\"18\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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