document.write( "Question 110375: Evaluate using the change of base formula. Round to 3 decimal places.\r
\n" ); document.write( "\n" ); document.write( "log3 3.5
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Algebra.Com's Answer #80469 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"log3%28+3.5%29\" ........the argument is \"3.5\"and the base is \"3\"\r
\n" ); document.write( "\n" ); document.write( " Plug them into \"change-of-base\" formula; \r
\n" ); document.write( "\n" ); document.write( "\"logb%28x%29+=+logd%28x%29%2Flogd%28b%29\"\r
\n" ); document.write( "\n" ); document.write( " I will use the natural log\r
\n" ); document.write( "\n" ); document.write( "\"log3%28+3.5%29=ln%283.5%29%2Fln%283%29+\" \r
\n" ); document.write( "\n" ); document.write( "\"log3%28+3.5%29=ln%283.5%29%2Fln%283%29+\"\r
\n" ); document.write( "\n" ); document.write( " \"log3%28+3.5%29=0.54406804435%2F+0.47712125472++\"\r
\n" ); document.write( "\n" ); document.write( " \"log3%28+3.5%29=1.1403139955885803468654996246653\"\r
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\n" ); document.write( "\n" ); document.write( "Then the answer, rounded to three decimal places, is:\r
\n" ); document.write( "\n" ); document.write( "\"log3%28+3.5%29=1.140\"\r
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