document.write( "Question 1176795: If the man’s age is a 3-digit number, his age is equal to product of two
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document.write( "numbers. One of the numbers is the sum of the digits and the other number is
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document.write( "product of the digits his age is? \n" );
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Algebra.Com's Answer #804669 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Ikleyn gave us one possibility above, 144. Let's see if we can find any\r\n" ); document.write( "others.\r\n" ); document.write( " \n" ); document.write( "the man’s age is a 3-digit number \n" ); document.write( " \r\n" ); document.write( "So he's at least 100 years old!\r\n" ); document.write( "\r\n" ); document.write( "Let h = the hundreds digit\r\n" ); document.write( "Let t = the tens digit\r\n" ); document.write( "Let u = the units or ones digit\r\n" ); document.write( "\r\n" ); document.write( "His age = 100h+10t+u\r\n" ); document.write( "His age = htu(h+t+u)\r\n" ); document.write( "\r\n" ); document.write( " 100h+10t+u = htu(h+t+u)\r\n" ); document.write( "(99+1)h+(9+1)t+u = htu(htu) \r\n" ); document.write( " 99h+h+9t+t+u = htu(h+t+u)\r\n" ); document.write( " 99h+9t+h+t+u = htu(h+t+u)\r\n" ); document.write( " 99h+9t = htu(h+t+u)-h-t-u\r\n" ); document.write( " 9(11h+t) = htu(h+t+u)-(h+t+u)\r\n" ); document.write( " 9(11h+t) = (h+t+u)(htu-1)\r\n" ); document.write( "\r\n" ); document.write( "Pretty complicated. Let's see if we can find any possibilities where he is\r\n" ); document.write( "less than 200 years old. That would mean that h=1. Substituting:\r\n" ); document.write( "\r\n" ); document.write( " 9(11+t) = (1+t+u)(tu-1)\r\n" ); document.write( "\r\n" ); document.write( "Let's see if there are any possibilities where the 1st and 2nd factors on\r\n" ); document.write( "the left are equal respectively to the 1st and 2nd factors on the right.\r\n" ); document.write( "[That is not necessarily the case, but it could be, and trying it may lead\r\n" ); document.write( "to more answers].\r\n" ); document.write( "\r\n" ); document.write( " 9 = 1+t+u, \r\n" ); document.write( "11+t = tu-1\r\n" ); document.write( "\r\n" ); document.write( "Solve the first equation for u\r\n" ); document.write( " 8-t = u\r\n" ); document.write( "\r\n" ); document.write( "Substitute in the second equation\r\n" ); document.write( "\r\n" ); document.write( " 11+t = t(8-t)-1\r\n" ); document.write( " 11+t = 8t-t2-1\r\n" ); document.write( " t2-7t+12 = 0 \r\n" ); document.write( "(t-4)(t-3) = 0\r\n" ); document.write( "\r\n" ); document.write( "t-4=0; t-3=0\r\n" ); document.write( " t=4; t=3\r\n" ); document.write( "\r\n" ); document.write( "If t=4, then 8-4 = u = 4. That gives us 144, which Ikleyn found above.\r\n" ); document.write( "We don't know how she found it. She just gave it.\r\n" ); document.write( "\r\n" ); document.write( "But we also have another possibility for t=3\r\n" ); document.write( "\r\n" ); document.write( "If t=3, then 8-3 = u = 5. That gives us the age of 135, which Ikleyn did\r\n" ); document.write( "not give above. \r\n" ); document.write( "\r\n" ); document.write( "The sum of the digits is 1+3+5 = 9 and the product is 1∙3∙5 = 15\r\n" ); document.write( "and 9∙15 = 135.\r\n" ); document.write( "\r\n" ); document.write( "So now we know that two possibilities are that the man is 135 or 144.\r\n" ); document.write( "\r\n" ); document.write( "I conjecture that 135 and 144 are the only possible solutions.\r\n" ); document.write( "\r\n" ); document.write( "In either case, he is older than any person has ever known to have lived to\r\n" ); document.write( "be. Jeanne Louise Calment (1875-1997) from France lived to be 122+. She is\r\n" ); document.write( "listed in Guinness's world records as having the longest life span on\r\n" ); document.write( "record. \r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |