document.write( "Question 1176837: Using the quadratic formula to solve for the roots.
\n" ); document.write( "Given \"3x%5E2%2B3x-2=0\"\r
\n" ); document.write( "\n" ); document.write( "I think it's ax2+bx+c=0 but I get lost on how to work it out.
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Algebra.Com's Answer #804663 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "The ax^2+bx+c = 0 is known as standard form for a quadratic. Compare that to what you were given and we see that
\n" ); document.write( "a = 3
\n" ); document.write( "b = 3
\n" ); document.write( "c = -2\r
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\n" ); document.write( "\n" ); document.write( "Those values are then plugged into the quadratic formula below. I broke up the \"plus/minus\" to form two separate equations.
\n" ); document.write( "\"x+=+%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\" or \"x+=+%28-b-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3%2Bsqrt%28%283%29%5E2-4%283%29%28-2%29%29%29%2F%282%283%29%29\" or \"x+=+%28-3-sqrt%28%283%29%5E2-4%283%29%28-2%29%29%29%2F%282%283%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3%2Bsqrt%2833%29%29%2F%286%29\" or \"x+=+%28-3-sqrt%2833%29%29%2F%286%29\" Exact Solutions\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3%2B5.74456264653803%29%2F%286%29\" or \"x+=+%28-3-5.74456264653803%29%2F%286%29\" Use a calculator from here.\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282.74456264653803%29%2F%286%29\" or \"x+=+%28-8.74456264653803%29%2F%286%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+0.457427107756338\" or \"x+=+-1.45742710775634\" Values are approximate\r
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\n" ); document.write( "\n" ); document.write( "So to recap, the exact solutions are:
\n" ); document.write( "\"x+=+%28-3%2Bsqrt%2833%29%29%2F%286%29\" or \"x+=+%28-3-sqrt%2833%29%29%2F%286%29\"
\n" ); document.write( "which approximate to
\n" ); document.write( "\"x+=+0.457427107756338\" or \"x+=+-1.45742710775634\"
\n" ); document.write( "in that exact order given
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