document.write( "Question 1176831: a) a baseball player hit a very high pop-up ball. H is the height in meters given by h(t) = 1+30t-5t^2 and t is the time in seconds. What height does this ball not reach?
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document.write( "b)if it is caught at the height it was hit, how long is it in the air. Round off to one decimal place.\r
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document.write( "I'm quite confused on how I can solve these, as I did try using the quadratic equation and it didn't work. \n" );
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Algebra.Com's Answer #804655 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! I'm assuming that the first part is what height does it reach. What it does not reach is everything else. \n" ); document.write( "h(t)=-5t^2+30t+1 \n" ); document.write( "vertex is at x=-b/2a or -30/-10 or at 3 seconds for t \n" ); document.write( "h(3)=-45+90+1 or 46 m height reached. \n" ); document.write( "set that equation equal to 1 \n" ); document.write( "there are two places where h(t)=1, at the bat and when caught. \n" ); document.write( "so h(t)=-5t^2+30t=-5t(t-6)=0 \n" ); document.write( "t=6.0 seconds, twice the time to get to the vertex, since this is symmetric at h(t)=1 m \n" ); document.write( " |