document.write( "Question 110400: I can not get this one to come out right. Can you help?\r
\n" ); document.write( "\n" ); document.write( "Factor.
\n" ); document.write( "-12x^3+36x^2\r
\n" ); document.write( "\n" ); document.write( "Thank you so much!
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Algebra.Com's Answer #80461 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\"-12x%5E3%2B36x%5E2\"
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\n" ); document.write( "First, enumerate the factors of the first term:
\n" ); document.write( "\"-1+%2A+2%2A2%2A3%2Ax%2Ax%2Ax\"
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\n" ); document.write( "Then the second term:
\n" ); document.write( "\"2%2A2%2A3%2A3%2Ax%2Ax\"
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\n" ); document.write( "Now, the two terms have the following factors in common: 2, 2, 3, x, x, so the quantity that you can factor out of both terms is \"12x%5E2\".
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\n" ); document.write( "This leaves you with:
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\n" ); document.write( "\"12x%5E2%28-x%2B3%29\", which is really good enough. However, I would also factor out th -1 by changing the signs on the two terms that remain in parentheses, thus:
\n" ); document.write( "\"-12x%5E2%28x-3%29\"
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