document.write( "Question 660008: a bag containing 275g of ice at 0 celsious was used to treat sore muscle. when the bag was removed the ice had melted and the liquid water has a temperature of 24. celsious, how many kilojoules of heat were absorbed? \n" ); document.write( "
Algebra.Com's Answer #804536 by CubeyThePenguin(3113)\"\" \"About 
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Q = m * C * (deltaT)\r
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\n" ); document.write( "\n" ); document.write( "m = mass of water
\n" ); document.write( "C = specific heat of water
\n" ); document.write( "delta T = change in temperature\r
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\n" ); document.write( "\n" ); document.write( "(0.275 kg)(4184 J/(kg * C))(24 C) = 27.6 kJ
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