document.write( "Question 1033140: The incomes of trainees at a local mill are normally distribution with a mean of $1,100 and a standard deviation $800. the percentage of trainees that earn $800 or less a month is ____%. \n" ); document.write( "
Algebra.Com's Answer #804523 by CubeyThePenguin(3113) You can put this solution on YOUR website! mean = 1100 \n" ); document.write( "-+ 1 standard deviation = 950 or 1250 \n" ); document.write( "-+ 2 standard deviations = 800 or 1400\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "According to the normal distribution, 2.5% of trainees make $800 or less a month.\r \n" ); document.write( "\n" ); document.write( " \n" );
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