document.write( "Question 110384: Ok, so town A and town B are 100 miles apart. Car A is leaving from town A and traveling 60mph, and car B is leaving from town B and traveling 50mph. How long before they collide? I know it has something to do with the D=r*t formula...I'm just not sure how to figure this one out. Thanks! \n" ); document.write( "
Algebra.Com's Answer #80447 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
They leave at the same time and collide at the same time, so
\n" ); document.write( "If I write\"t+=+d%5BA%5D%2Fr%5BA%5D\" and \"t+=+d%5BB%5D%2Fr%5BB%5D\", then
\n" ); document.write( "t is the same for both, and I can write \"d%5BA%5D%2Fr%5BA%5D+=+d%5BB%5D%2Fr%5BB%5D\"
\n" ); document.write( "and \"r%5BA%5D+=+60\", \"r%5BB%5D+=+50\", so
\n" ); document.write( "\"d%5BA%5D%2F60+=+d%5BB%5D%2F50\"
\n" ); document.write( "And I know \"d%5BA%5D+%2B+d%5BB%5D+=+100\", so I can say
\n" ); document.write( "\"d%5BB%5D+=+100+-+d%5BA%5D\"
\n" ); document.write( "Now I have \"d%5BA%5D+%2F+60+=+%28100+-+d%5BA%5D%29+%2F+50\"
\n" ); document.write( "\"50%2Ad%5BA%5D+=+60%28100+-+d%5BA%5D%29\"
\n" ); document.write( "\"50%2Ad%5BA%5D+=+6000+-+60%2Ad%5BA%5D\"
\n" ); document.write( "\"110%2Ad%5BA%5D+=+6000\"
\n" ); document.write( "\"d%5BA%5D+=+54.5454\"
\n" ); document.write( "\"t+=+d%5BA%5D+%2F+r%5BA%5D\"
\n" ); document.write( "\"t+=+54.5454+%2F+60\"
\n" ); document.write( "\"t+=+.90909\"hrs
\n" ); document.write( "\".90909\"hrs x \"60\"min/hr = \"54.5454\"min
\n" ); document.write( "\".5454\" min x \"60\"sec/min = 32.7272 sec
\n" ); document.write( "So, the cars will collide in 54 min 33 sec approximately
\n" ); document.write( "
\n" );