document.write( "Question 487617: how to solve this equation:
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Algebra.Com's Answer #804465 by ikleyn(52781) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( " @ThePenguin solved the problem incorrectly, by incorrectly presenting the second solution and by loosing the third solution.\r
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document.write( "Let ln(x) = y.\r\n" );
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document.write( "3y^3 - 4y^2 - 5y + 2 = 0\r\n" );
document.write( "(y - 2)(3y - 1)(y + 1) = 0\r\n" );
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document.write( "y = 2, y = 1/3, or y = -1\r\n" );
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document.write( "        Consider all three cases separately. \r\n" );
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document.write( "1)  ln(x) = 2    ---->  x = e^2.\r\n" );
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document.write( "2)  ln(x) = 1/3 ---->  x = e^(1/3) = .\r\n" );
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document.write( "3)  ln(x) = -1  ---->  x = e^(-1) = 1/e.\r\n" );
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