document.write( "Question 110378: 17. A line passing through (13, 16) and (9, y) is parallel to a line with slope 2. What is the value of y? \n" ); document.write( "
Algebra.Com's Answer #80442 by jim_thompson5910(35256)\"\" \"About 
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\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\" Start with the slope formula (note: is the first point (\"13\",\"16\") and is the second point (\"9\",y))\r
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\n" ); document.write( "\n" ); document.write( "\"2=%28y-16%29%2F%289-13%29\" Plug in \"y%5B2%5D=y\",\"y%5B1%5D=16\",\"x%5B2%5D=9\",\"x%5B1%5D=13\" (these are the coordinates of given points). Now plug in \"m=2\" (this is the given slope)\r
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\n" ); document.write( "\n" ); document.write( "\"2=+%28y-16%29%2F-4\" Subtract the terms in the denominator \"9-13\" to get \"-4\"\r
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\n" ); document.write( "\n" ); document.write( "\"-8=y-16\" Multiply both sides by -4\r
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\n" ); document.write( "\n" ); document.write( "\"8=y\" Add 16 to both sides\r
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\n" ); document.write( "\n" ); document.write( "So the value of y is \"y=8\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we find the slope of (\"13\",\"16\") and (\"9\",\"8\"), we get\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\" Start with the slope formula (note: is the first point (\"13\",\"16\") and is the second point (\"9\",\"8\"))\r
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\n" ); document.write( "\n" ); document.write( "\"m=%288-16%29%2F%289-13%29\" Plug in \"y%5B2%5D=8\",\"y%5B1%5D=16\",\"x%5B2%5D=9\",\"x%5B1%5D=13\" (these are the coordinates of given points)\r
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\n" ); document.write( "\n" ); document.write( "\"m=+-8%2F-4\" Subtract the terms in the numerator \"8-16\" to get \"-8\". Subtract the terms in the denominator \"9-13\" to get \"-4\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=2\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the slope is\r
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\n" ); document.write( "\n" ); document.write( "So our answer is verified
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