document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=110232>Question 110232</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one number is 12morethan half another number.the two numbers total 60.find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #80439 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=80439\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=the second number\r<BR>\n" );
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document.write( "Then (x/2)+12=the first number\r<BR>\n" );
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document.write( "Now we are told that:<BR>\n" );
document.write( "x+(x/2)+12=60  subtract 12 from both sides\r<BR>\n" );
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document.write( "x+(x/2)+12-12=60-12 collect like terms\r<BR>\n" );
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document.write( "(3x/2)=48 multiply both sides by 2<BR>\n" );
document.write( "3x=96  divide both sides by 3<BR>\n" );
document.write( "x=32-------------the second number\r<BR>\n" );
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document.write( "(x/2)+12=(32/2)+12=16+12=28 the first number\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "28+32=60<BR>\n" );
document.write( "60=60\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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