document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=487617>Question 487617</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to solve this equation: <BR>\n" );
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document.write( "3(ln2x)^3-4(ln2x)^2-5ln2x+2=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #804328 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=804328\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let ln(x) = y.\r<BR>\n" );
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document.write( "3y^3 - 4y^2 - 5y + 2 = 0<BR>\n" );
document.write( "(y - 2)(3y - 1)(y + 1) = 0\r<BR>\n" );
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document.write( "y = 2, y = 1/3, or y = -1\r<BR>\n" );
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document.write( "ln(x) cannot be negative, eliminating the last case.\r<BR>\n" );
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document.write( "ln(x) = 2 ----> x = e^2<BR>\n" );
document.write( "ln(x) = 1/3 ----> x = 1/(e^3) </SPAN>\n" );
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