document.write( "Question 1176772: Part 1: Binomial Probabilities \r
\n" ); document.write( "\n" ); document.write( "A survey said that 3 in 5 students enrolled in higher education took at least one online course last fall. (Remember that we converted the ratio into a percentage to find the probability that a student took an online class.)\r
\n" ); document.write( "\n" ); document.write( "Choose 4 students at random. \r
\n" ); document.write( "\n" ); document.write( "a) All 4 students took online courses\r
\n" ); document.write( "\n" ); document.write( "b) None of the 4 students took online courses\r
\n" ); document.write( "\n" ); document.write( "c) At least 1 of the 4 students took an online course\r
\n" ); document.write( "\n" ); document.write( "Include in your discussion what you used for n and p in the binomial distribution and any calculations you used. \r
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\n" ); document.write( "\n" ); document.write( "Part 2: Use the Standard Normal Table (attached to the end of packet 2). \r
\n" ); document.write( "\n" ); document.write( "To qualify for security officers’ training, recruits are tested for stress tolerance. The scores are normally distributed, with a mean of 62 and a standard deviation of 8. Find the probability that a randomly selected recruit has a score between 64 and 72. Include a detailed description of how you calculated the probability (not just the final answer).\r
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Algebra.Com's Answer #804231 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Hi\r\n" );
document.write( "1) Binomial Distribution:   p = .6  and n = 4\r\n" );
document.write( "\"P+%28x%29=+highlight_green%28nCx%29%28p%5Ex%29%28q%29%5E%28n-x%29+\" \r\n" );
document.write( " a) P(x = 4) = 4C4 (.6)^4(.4)^0 = .1296\r\n" );
document.write( "0r TI: P(x = 4) = (4,.6,4)\r\n" );
document.write( " b) P( x = 0) = 4C0 9.60^0(.40)^4 = .0256\r\n" );
document.write( " c) P( x ≥   1) = 1 - P(x=0) = 1 - .0256 = .9744\r\n" );
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document.write( "2) Normal distribution:  mean of 62 and a standard deviation of 8.\r\n" );
document.write( " P(64< x < 72) = normalcdf(64,72,62,8) =  .2956        |Using TI\r\n" );
document.write( "that is:\r\n" );
document.write( "  P(x ≤ 72) - P( x≤ 64)  0r   P(z ≤ 10/8) - P(z ≤ 2/8)  \"z+=blue+%28x+-+mu%29%2Fblue%28sigma%29\"\r\n" );
document.write( "Using Calculator/ Table to complete either.\r\n" );
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document.write( "Wish You the Best in your Studies.\r\n" );
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