document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1046401>Question 1046401</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2*(3)^2x-8=2*(3)^x+1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #804200 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=804200\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3^x = y\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "2y^2 - 8 = 2y + 1<BR>\n" );
document.write( "2y^2 - 2y - 9 = 0\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Use the quadratic formula: y = 1/2 + sqrt(19)/2 or 1/2 - sqrt(19)/2.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "y has to be positive, so: x^3 = 1/2 + sqrt(19)/2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x = (1/2 + sqrt(19)/2)^(1/3) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );