document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1047564>Question 1047564</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -3(-2-2^0 x)-(-2)-2(-2-3x)=-2(x+4) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #804194 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=804194\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -3(-2- x)-(-2)-2(-2-3x)=-2(x+4)<BR>\n" );
document.write( "(6 + 3x) + (2) + (4 + 6x) = -2x - 8<BR>\n" );
document.write( "9x + 12 = -2x - 8<BR>\n" );
document.write( "11x = -20\r<BR>\n" );
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document.write( "x = -20/11 </SPAN>\n" );
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