document.write( "Question 110341: I would appreciate any help with this problem.\r
\n" ); document.write( "\n" ); document.write( "Solve by completing the square
\n" ); document.write( "4x^2+2x-3=0
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Algebra.Com's Answer #80413 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"4x%5E2+%2B+2x+-+3+=+0\"
\n" ); document.write( "divide both sides by 4
\n" ); document.write( "\"x%5E2+%2B%281%2F2%29x+-+%283%2F4%29+=+0\"
\n" ); document.write( "add 3/4 to both sides
\n" ); document.write( "\"x%5E2+%2B+%281%2F2%29x+=+3%2F4\"
\n" ); document.write( "Now take 1/2 of the coefficient of x, square it, and add to both sides
\n" ); document.write( "\"x%5E2+%2B+%281%2F2%29x+%2B+%281%2F16%29+=+%283%2F4%29+%2B+%281%2F16%29\"
\n" ); document.write( "\"x%5E2+%2B+%281%2F2%29x+%2B+%281%2F16%29+=+13%2F16\"
\n" ); document.write( "\"%28x+%2B+%281%2F4%29%29%5E2+=+13%2F16\"
\n" ); document.write( "take the square root of both sides
\n" ); document.write( "\"x+%2B+%281%2F4%29+=+%2B+sqrt%2813%2F16%29\"
\n" ); document.write( "\"x+%2B+%281%2F4%29+=+-+sqrt%2813%2F16%29\" both of these are true
\n" ); document.write( "solve for x
\n" ); document.write( "\"x+=+-%281%2F4%29+%2B+%28sqrt%2813%29%29%2F4\"
\n" ); document.write( "\"x+=+%28-1+%2B+sqrt%2813%29%29+%2F+4\" answer
\n" ); document.write( "and
\n" ); document.write( "\"x+=+-%281%2F4%29+-+%28sqrt%2813%29%29%2F4\"
\n" ); document.write( "\"x+=+%28-1+-+sqrt%2813%29%29+%2F+4\" answer
\n" ); document.write( "You can check answers by plugging both (one at a time) into
\n" ); document.write( "the original equation. I checked one of them & checked OK
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