document.write( "Question 1176731: Ann has $3.20 in 10 cents coins and 25 cents coins. If she has twenty coins
\n" ); document.write( "altogether, find how many of each type of coin she has.
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Algebra.Com's Answer #804085 by MathLover1(20850)\"\" \"About 
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\r
\n" ); document.write( "\n" ); document.write( "let \"10\" cents coins be \"d\" and \"25\" cents coins \"q\"\r
\n" ); document.write( "\n" ); document.write( "if she has twenty coins altogether, we have\r
\n" ); document.write( "\n" ); document.write( "\"d%2Bq=20\"
\n" ); document.write( "\"d=20-q\"....eq.1\r
\n" ); document.write( "\n" ); document.write( "\"1d\"=$\"0.10\"
\n" ); document.write( "\"1q\"=$\"0.25\"\r
\n" ); document.write( "\n" ); document.write( "if Ann has $\"3.20\", then\r
\n" ); document.write( "\n" ); document.write( "\"0.10d%2B0.25q=3.20\".....substitute \"d\" from eq.1\r
\n" ); document.write( "\n" ); document.write( "\"0.10%2820-q%29%2B0.25q=3.20\"\r
\n" ); document.write( "\n" ); document.write( "\"2-0.10q%2B0.25q=3.20\"\r
\n" ); document.write( "\n" ); document.write( "\"0.15q=3.20-2\"\r
\n" ); document.write( "\n" ); document.write( "\"0.15q=1.20\"...both sides multiply by \"100\" to get rid of decimals\r
\n" ); document.write( "\n" ); document.write( "\"15q=120\"\r
\n" ); document.write( "\n" ); document.write( "\"q=120%2F15\"\r
\n" ); document.write( "\n" ); document.write( "\"q=8\"\r
\n" ); document.write( "\n" ); document.write( "go to eq.1\r
\n" ); document.write( "\n" ); document.write( "\"d=20-q\"....eq.1, substitute \"q\"
\n" ); document.write( "\"d=20-8\"
\n" ); document.write( "\"d=12\"\r
\n" ); document.write( "\n" ); document.write( "so Ann has \"12\" of \"10\" cents coins and \"8\" of \"25\" cents coins\r
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