document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030658>Question 1030658</A>: <I><SPAN STYLE=\"word-break: break-all;\"> While gerald was at the post office he purchased some 40 cent stamps and three times as many 30 cent stamps. in all the stamps cost $20.80. how many of each did he buy </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #804064 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=804064\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = number of 30 cent stamps<BR>\n" );
document.write( "y = number of 40 cent stamps\r<BR>\n" );
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document.write( "x = 3y<BR>\n" );
document.write( "30x + 40y = 2080\r<BR>\n" );
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document.write( "Use substitution.\r<BR>\n" );
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document.write( "30(3y) + 40y = 2080<BR>\n" );
document.write( "130y = 2080<BR>\n" );
document.write( "y = 16\r<BR>\n" );
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document.write( "Gerald bought 48 30-cent stamps and 16 40-cent stamps. </SPAN>\n" );
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