document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1160926>Question 1160926</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cup of coffee is poured at 190˚F and is allowed to cool in a 70˚F room. If the temperature of the coffee is 170˚F after half an hour,<BR>\n" );
document.write( " (a) What will the temperature be after 70 minutes?<BR>\n" );
document.write( " (b)How long it will take the coffee to cool to 120 ˚F?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #804043 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=804043\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 190 F after 0 minutes, 170 F after 30 minutes --> decrease of 2/3 degrees every minute\r<BR>\n" );
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document.write( "a) 190 - 70(2/3) = 430/3 = 143 1/3 degrees \r<BR>\n" );
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document.write( "b) 190 - (2/3)x = 120<BR>\n" );
document.write( "70 = 2x/3<BR>\n" );
document.write( "210 = 2x\r<BR>\n" );
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document.write( "x = 105 minutes </SPAN>\n" );
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