document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1176709>Question 1176709</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a salesman has a 20% probability of making a sale to any customer who enters his department. non a typical day, he will meet 30 customers. what minimum number of sales will he have an 88% certainly of making for any given day. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #803992 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=803992\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> binomial with n=30 and p=0.2<BR>\n" );
document.write( "Expected mean is 6<BR>\n" );
document.write( "expected variance is 4.8 (6*0.8)<BR>\n" );
document.write( "expected sd is sqrt (V) or 2.19<BR>\n" );
document.write( "p(0 sales) is 0.8^30=0.0012<BR>\n" );
document.write( "p(1)=0.8^29*0.2*30=0.0093<BR>\n" );
document.write( "p(2)=0.8^28*0.2^2*30C2=0.0337<BR>\n" );
document.write( "p(3)=0.8^27*0.2^3*30C3=0.0785<BR>\n" );
document.write( "p(4) from calculator is 0.1325<BR>\n" );
document.write( "It would be 3 with a probability the sum of the first four, which is 0.1227<BR>\n" );
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