document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=110321>Question 110321</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 7x+9y=26<BR>\n" );
document.write( "x=32-6y<BR>\n" );
document.write( "Solve for y and x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #80385 by </B><A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><B>malakumar_kos@yahoo.com(315)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=80385\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 7x+9y=26<BR>\n" );
document.write( "x=32-6y<BR>\n" );
document.write( "Solve for y and x\r<BR>\n" );
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document.write( "    we have to find the values of x&y  so we will use ellimination method\r<BR>\n" );
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document.write( "     7x+9y = 26......(1)\r<BR>\n" );
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document.write( "     x+6y = 32.......(2)  {got by transfering 6y to left hand side}\r<BR>\n" );
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document.write( "  multiply (2) by 7 and subtract (1)  & (3)  hence (2) becomes 7x+42y= 224..(3)\r<BR>\n" );
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document.write( "   subtracting 1& 3 we get -33y = -198  or y = -198/-33 = 6\r<BR>\n" );
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document.write( "   substitute for y in (2) we get  x = 32- 6(6) = 32-36 = -4\r<BR>\n" );
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document.write( "    therefore the values of x& y are x = -4 and y = 6\r<BR>\n" );
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document.write( " </SPAN>\n" );
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