document.write( "Question 110304: I really need help with this.\r
\n" ); document.write( "\n" ); document.write( "The radiatr of a jeep that has a capacity of 8 gallons is full with a solution of 10% antifreeze. How much must be drained and replaced by pure antifreeze to obtain a 25% solution?
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Algebra.Com's Answer #80384 by wgunther(43)\"\" \"About 
You can put this solution on YOUR website!
f(x)=.8-.1x, where x is the amount drained, so f is the amount of an anti-freeze stil in the car. We're assuming that this mixtured is \"well mixed\" of course. \r
\n" ); document.write( "\n" ); document.write( "The amount of fluid drained is equal to the amount of antifreeze we are adding. So .8-.1x+x= the amount of antifreeze in the car after refilling it. We want this number, divided by 8 to be .25. So. .8+.9x=8(.25)), which is 1.333...
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