document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1176453>Question 1176453</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You are concerned that nausea may be a side effect of Tamiflu, but you cannot just give Tamiflu to patients with the flu and say that nausea is a side effect if people become nauseous. This is because nausea is common for people who have the flu. From past studies you know that about 30% of people who get the flu experience nausea. You collected data on 1595 patients who were taking Tamiflu to relieve symtoms of the flu, and found that 525 experienced nausea. Use a 0.01 significance level to test the claim that the percentage of people who take Tamiflu for the relief of flu symtoms and experience nausea is greater than 30%. \r<BR>\n" );
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document.write( "Calculate your test statistic. Write the result below, and be sure to round your final answer to two decimal places.\r<BR>\n" );
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document.write( "Calculate your p-value. Write the result below, and be sure to round your final answer to four decimal places.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #803831 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=803831\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Point estimate is p hat=525/1595=0.32915<BR>\n" );
document.write( "Ho: p<=0.30<BR>\n" );
document.write( "Ha: p>0.30<BR>\n" );
document.write( "alpha=0.01 p{reject Ho|Ho true}<BR>\n" );
document.write( "test statistic is a z<BR>\n" );
document.write( "critical value is z>2.326<BR>\n" );
document.write( "z=(p hat-p)/sqrt(p*(1-p)/n)<BR>\n" );
document.write( "=0.02915/sqrt( (0.3*0.7/1595); sqrt term =0.01147<BR>\n" );
document.write( "z=2.54<BR>\n" );
document.write( "reject Ho<BR>\n" );
document.write( "p-value z>2.540 which is 0.0055. </SPAN>\n" );
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