document.write( "Question 1176629: Find the quadratic function y​=f(x) whose graph has a vertex ​(-2​,​4) and passes through the point ​(-6​,0). Write the function in standard form. \n" ); document.write( "
Algebra.Com's Answer #803812 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi\r
\n" ); document.write( "\n" ); document.write( "Using the vertex form of a parabola, \"y=a%28x-h%29%5E2+%2Bk\" where(h,k) is the vertex
\n" ); document.write( "Vertex (-2,4)
\n" ); document.write( " y = a(x+2)^2 + 4
\n" ); document.write( "P​(-6​,0)
\n" ); document.write( "0 = 16a+ 4
\n" ); document.write( "-4/16 = a = -.25\r
\n" ); document.write( "\n" ); document.write( "\"y+=+-.25%28x%2B2%29%5E2+%2B+4\", the vertex form of a parabola\r
\n" ); document.write( "\n" ); document.write( "As to Standard form (If necessary):
\n" ); document.write( " y =-.25(x^2 + 4x + 4) + 1 =-.25x^2 - x - 1 + 4 = -.25x^2 - x + 3
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