document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=110318>Question 110318</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the domain of   3x/x^2+1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #80381 by </B><A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><B>malakumar_kos@yahoo.com(315)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=80381\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the domain of   3x/x^2+1\r<BR>\n" );
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document.write( "f(x) = 3x/x^2+1  the values of x are called range and the corresponding values of f(x) are called domain.\r<BR>\n" );
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document.write( "let us take the values of x as {0,1,2,3,4,5}\r<BR>\n" );
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document.write( "  if x = 0 then  f(x) = 3(0)/0^2+1 = 0/1 = 0\r<BR>\n" );
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document.write( "  if x = 1 then f(x) = 3(1)/1^2+1 = 3/1+1= 3/2\r<BR>\n" );
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document.write( "  if x= 2  then f(x) = 3(2)/2^2+1 = 6/4+1 = 6/5\r<BR>\n" );
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document.write( "  if x= 3 then f(x) = 3(3)/3^2+1 =  9/9+1 = 9/10\r<BR>\n" );
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document.write( "  if x= 4 then f(x) = 3(4)/4^2+1 = 12/16+1 = 12/17\r<BR>\n" );
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document.write( "  if x= 5 then f(x) = 3(5)/5^2+1 = 15/25+1 = 15/26\r<BR>\n" );
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document.write( "   the domain is {0,3/2,6/5,9/10,12/17,15/26}<BR>\n" );
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