document.write( "Question 1176603: Suppose a football player has a 65% chance of making a goal that he can keep each time he tries to make a goal. What is the probability that he makes a goal for the first three times he tries to but not on the fourth try? \n" ); document.write( "

Algebra.Com's Answer #803786 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Hi\r\n" );
document.write( "Obviously, this presentation is for the interpretation:\r\n" );
document.write( "\"he makes a goal for the first three times\"  \r\n" );
document.write( "as making 3 goals before missing. Obviously making the 1st 3 goals is more exciting.\r\n" );
document.write( "Binomial Distribution:  p = .65,  n = 4\r\n" );
document.write( "P(x= 3) = binompdf(4, .65, 3) = .3845\r\n" );
document.write( "there are four ways x=3 can be done: NG in 1st, 2nd, 3rd, or 4th position\r\n" );
document.write( " P(G,G,G,NG) = .3845/4 = .0961\r\n" );
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document.write( "It is fun to see different ways of approaching a problem:\r\n" );
document.write( "In case of the other tutor:\r\n" );
document.write( " 1st Step:  making 3 in a row:  should be: 3C3(.65)^3(.35)^0 = .274625\r\n" );
document.write( " 2nd Step:  (.35)(.274625) = .0961  same final answer.\r\n" );
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document.write( "Wish You the Best in your Studies.\r\n" );
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