document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1017128>Question 1017128</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If g(x) is the inverse of f(x)=&#8730;(x^3) + 1 . <BR>\n" );
document.write( "which of the following is on g(x)? \r<BR>\n" );
document.write( "\n" );
document.write( "A). (4,9) <BR>\n" );
document.write( "B). (9,4)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #803761 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=803761\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The easiest way would be to plug in both points after finding the inverse.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "y = sqrt(x^3) + 1<BR>\n" );
document.write( "y - 1 = sqrt(x^3)<BR>\n" );
document.write( "(y - 1)^2 = x^3<BR>\n" );
document.write( "(y - 1)^(2/3) = x\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "g^(-1)(x) = cbrt((x - 1)^2)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "g^(-1)(4) = cbrt(3^2) = cbrt(9)<BR>\n" );
document.write( "g^(-1)(9) = cbrt(8^2) = 4\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The point (9, 4) is on g^(-1)(x). </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );