document.write( "Question 1176576: Find the standard form of the equation of the hyperbola with the given characteristics.\r
\n" ); document.write( "\n" ); document.write( "Foci: (±10, 0); asymptotes: y = ±4/3x
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #803731 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "There are two standard forms:\r
\n" ); document.write( "\n" ); document.write( " 1. \"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( " 2. = ±\"+m%28x-h%29%2Bk\"\r
\n" ); document.write( "\n" ); document.write( "Therefore, the equation, \"y\" = ±\"%284%2F3%29x\" tell us that h=0 and k=0
\n" ); document.write( " The center is the point (\"0\",\"0\").\r
\n" ); document.write( "\n" ); document.write( "Foci is given to be, (±\"10\", \"0\"), tells us that the hyperbola is the horizontal transverse type with the equation in item 1\r
\n" ); document.write( "\n" ); document.write( "\"%28x-0%29%5E2%2Fa%5E2-%28y-0%29%5E2%2Fb%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Fa%5E2-y%5E2%2Fb%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( "The distance to the focus is linear eccentricity \"c\".
\n" ); document.write( "The point (10, 0) shows us the value of \"c=10\":\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2=a%5E2%2Bb%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"y+\"= ±\"%284%2F3%29x\" shows us that\r
\n" ); document.write( "\n" ); document.write( "->\"b%2Fa=4%2F3\"
\n" ); document.write( "\"b=4a%2F3\"
\n" ); document.write( "\"10%5E2=a%5E2%2B%284a%2F3%29%5E2\"
\n" ); document.write( "\"100=a%5E2%2B16a%5E2%2F9\"
\n" ); document.write( "\"100=25a%5E2%2F9\"
\n" ); document.write( "\"900%2F25=a%5E2\"
\n" ); document.write( "\"36=a%5E2\"
\n" ); document.write( "\"a=6\"\r
\n" ); document.write( "\n" ); document.write( "then\r
\n" ); document.write( "\n" ); document.write( "\"b%2F6=4%2F3\"
\n" ); document.write( "\"b=24%2F3\"
\n" ); document.write( "\"b=8\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F6%5E2-y%5E2%2F8%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( "and your equation in standard form is: \r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F36-y%5E2%2F64=1\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );